document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=454727>Question 454727</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if tanA= 5/12, find sin2a </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #312183 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=312183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if tanA= 5/12, find sin(2a)<BR>\n" );
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document.write( "If tan(A) = 5/12, y = 5 when x = 12<BR>\n" );
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document.write( "Then r = sqrt[5^2+12^2] = sqrt[169] = 13<BR>\n" );
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document.write( "So, sin(A) = y/r = 5/13 <BR>\n" );
document.write( "and cos(A) = x/r = 12/13<BR>\n" );
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document.write( "Therefore sin(2A) = 2*sin(A)*cos(A) = 2*(5/13)(12/13) = 120/169 = 0.7101<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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