document.write( "Question 454467: 9) The time spent by students on a particular E270 homework assignment follows a normal distribution with a mean μ = 150 minutes and standard deviation σ = 40 minutes. Then 90% of student finish the assignment within ± _____ minutes from the mean time period.
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document.write( "a 41.6
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document.write( "b 51.2
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document.write( "c 65.6
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document.write( "d 78.6
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document.write( "10) On a different homework assignment the standard deviation of the time spent is 30 minutes. If 20% of students finish the assignment under 115 minutes, then the mean time spent on this assignment is _____ minutes.
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document.write( "a 157
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document.write( "b 153
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document.write( "c 146
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document.write( "d 140
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Algebra.Com's Answer #312137 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The time spent by students on a particular E270 homework assignment follows a normal distribution with a mean μ = 150 minutes and standard deviation σ = 40 minutes. Then 90% of student finish the assignment within ± _____ minutes from the mean time period. \n" ); document.write( "--- \n" ); document.write( "Draw the picture of a normal curve. \n" ); document.write( "Center 90% around the mean. \n" ); document.write( "That leaves a right and a left tail or 5%. \n" ); document.write( "--- \n" ); document.write( "The z-value cutoffs are +/-1.645 \n" ); document.write( "The corresponding minute values are: \n" ); document.write( "x = 1.645*40 = 65.8 minutes \n" ); document.write( "------------------------------------\r \n" ); document.write( "\n" ); document.write( "a 41.6 \n" ); document.write( "b 51.2 \n" ); document.write( "c 65.6 \n" ); document.write( "d 78.6 \n" ); document.write( "------------------------------------ \r \n" ); document.write( "\n" ); document.write( "10) On a different homework assignment the standard deviation of the time spent is 30 minutes. If 20% of students finish the assignment under 115 minutes, then the mean time spent on this assignment is _____ minutes. \n" ); document.write( "--- \n" ); document.write( "Find the z-value with a 20% left tail. \n" ); document.write( "z = -0.8416 \n" ); document.write( "------ \n" ); document.write( "Using x = zs+u \n" ); document.write( "115 = -0.8416*30 + u \n" ); document.write( "u = 115 + 25.25 \n" ); document.write( "u = 140.25 mminutes \n" ); document.write( "================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============== \n" ); document.write( " \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a 157 \n" ); document.write( "b 153 \n" ); document.write( "c 146 \n" ); document.write( "d 140 \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |