document.write( "Question 428023: Mary has $2.15 in change consisting of 11 more dimes than nickels. Find the number of nickels and dimes. how do you set up this problem and solve it? \n" ); document.write( "
Algebra.Com's Answer #312100 by jorel1380(3719) You can put this solution on YOUR website! Assuming Mary has only nickels and dimes,then: \n" ); document.write( "nickels=x \n" ); document.write( "dimes=x+11 \n" ); document.write( "5x+10(x+11)=215 \n" ); document.write( "15x+110=215 \n" ); document.write( "15x=105 \n" ); document.write( "x=7 \n" ); document.write( "x+11=18 \n" ); document.write( "Mary has 7 nickels, and 18 dimes.. \n" ); document.write( " |