document.write( "Question 454341: Two persons are to a run a race but one can run 10 meters per second, whereas the other can run 6 meters per second. If the slower runner has a 70-meter head start, how long will it be before the faster runner catches up to the slower runner, if they begin at the same time. \n" ); document.write( "

Algebra.Com's Answer #312037 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Two persons are to a run a race but one can run 10 meters per second, whereas the other can run 6 meters per second.
\n" ); document.write( " If the slower runner has a 70-meter head start, how long will it be before the
\n" ); document.write( " faster runner catches up to the slower runner, if they begin at the same time.
\n" ); document.write( ":
\n" ); document.write( "Let t = time (in sec) for the faster runner to catch the slower
\n" ); document.write( ":
\n" ); document.write( "When this occurs they will have ran the same distance, Write distance equation,
\n" ); document.write( "Dist = speed*time
\n" ); document.write( ":
\n" ); document.write( "10t = 6t + 70
\n" ); document.write( "10t - 6t = 70
\n" ); document.write( "4t = 70
\n" ); document.write( "t = $\"70%2F4\"$
\n" ); document.write( "t = 17.5 seconds
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this using relative speed
\n" ); document.write( "their relative speed (to each other) is 4 m/sec
\n" ); document.write( "How long will it take to cover 70 m at 4 m/sec \n" ); document.write( "

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