document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=454426>Question 454426</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help solving the system listed below using the elimination method.  I have a particulary hard time when I have to substitute the value of x in the equations.\r<BR>\n" );
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document.write( "5x + 5y = -7<BR>\n" );
document.write( "7x - 3y = 11 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #312034 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=312034\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x + 5y = -7<BR>\n" );
document.write( "7x - 3y = 11<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "Multiply 1st equation by 7<BR>\n" );
document.write( "Multiply 2nd equation by 5<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "35x + 35y = -49<BR>\n" );
document.write( "35x - 15y = 55<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Subtract and solve for \"y\":<BR>\n" );
document.write( "50y = -104<BR>\n" );
document.write( "y = -52/25<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Solve for \"x\":<BR>\n" );
document.write( "5x + 5(-52/25) = -7<BR>\n" );
document.write( "5x - 52/5 = -35/5<BR>\n" );
document.write( "---<BR>\n" );
document.write( "5x = 17/5<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x = 17/25<BR>\n" );
document.write( "================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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