document.write( "Question 454404: Determine how many solutions exist, and use either elimination or substitution to find the solutions (if any).\r
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\n" ); document.write( "\n" ); document.write( "x + y = 3 and y = x + 3
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Algebra.Com's Answer #312025 by mananth(16946)\"\" \"About 
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x+y=3 .............1
\n" ); document.write( "-x+y=3 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -1
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "-1 x -1 y = -3
\n" ); document.write( "-1 x 1 y = 3
\n" ); document.write( "Add the two equations
\n" ); document.write( "-2x =0
\n" ); document.write( "/-2
\n" ); document.write( "x= 0.00
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "x+y=3
\n" ); document.write( "y=3\r
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\n" ); document.write( "\n" ); document.write( "unique solution ( 0,3)
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