document.write( "Question 454351: How do you solve;\r
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document.write( "sin(x)+sin(2x)=0\r
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document.write( "I understand that sin(2x)=2sin(x)cos(x), so here is what I have right now:\r
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document.write( "sin(x)+2sin(x)cos(x)=0\r
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document.write( "I don't understand how to factor it any further. \n" );
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Algebra.Com's Answer #312013 by stanbon(75887) ![]() You can put this solution on YOUR website! sin(x)+2sin(x)cos(x)=0 \n" ); document.write( "I don't understand how to factor it any further. \n" ); document.write( "------------------ \n" ); document.write( "Factor out the common factor, sin(x): \n" ); document.write( "----- \n" ); document.write( "sin(x)[1+2cos(x)] = 0 \n" ); document.write( "--- \n" ); document.write( "sin(x) = 0 or 1+2cos(x) = 0 \n" ); document.write( "--- \n" ); document.write( "sin(x) = 0 or cos(x) = -1/2 \n" ); document.write( "--- \n" ); document.write( "x = 0, or 180 or 240 or 300 degrees \n" ); document.write( "====================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========== \n" ); document.write( " |