document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=454313>Question 454313</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the linear system by using substitution. x=6-4y, 2x-3y=1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #311963 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=311963\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = 6 - 4y<BR>\n" );
document.write( "2x - 3y = 1\r<BR>\n" );
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document.write( "2x - 3y = 1 {bottom equation}<BR>\n" );
document.write( "2(6 - 4y) - 3y = 1 {substituted 6 - 4y, in for x, into bottom equation}<BR>\n" );
document.write( "12 - 8y - 3y = 1 {used distributive property}<BR>\n" );
document.write( "12 - 11y = 1 {combined like terms}<BR>\n" );
document.write( "-11y = -11 {subtracted 12 from both sides}<BR>\n" );
document.write( "y = 1 {divided both sides by -11}\r<BR>\n" );
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document.write( "x = 6 - 4y {top equation}<BR>\n" );
document.write( "x = 6 - 4(1) {substituted 1, in for y, into top equation}<BR>\n" );
document.write( "x = 6 - 4 {multiplied 4 by 1}<BR>\n" );
document.write( "x = 2 {subtracted}\r<BR>\n" );
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document.write( "x = 2 and y = 1<BR>\n" );
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