document.write( "Question 454258: solve using substitution method\r
\n" ); document.write( "\n" ); document.write( "x - 5y = 17
\n" ); document.write( "-5x - 6y = 8 \n" ); document.write( "
Algebra.Com's Answer #311957 by mananth(16946)\"\" \"About 
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x-5y=17 .............1
\n" ); document.write( "6y=-8-5x ---------2
\n" ); document.write( "/6=
\n" ); document.write( "y=-1.33 -0.83x
\n" ); document.write( "Plug the value of y in (1)
\n" ); document.write( "x-5(-1.33-0.83x) =17
\n" ); document.write( "x+6.67+ 4.17x=17
\n" ); document.write( "x+4.17x= 17-6.67
\n" ); document.write( "5.17x=10.33
\n" ); document.write( "/5.17
\n" ); document.write( "x=2
\n" ); document.write( "Plug the value of x in (1)
\n" ); document.write( "x-5y=17
\n" ); document.write( "1*2-5y=17
\n" ); document.write( "2-5y=17
\n" ); document.write( "-5y=15
\n" ); document.write( "/-5
\n" ); document.write( "y=-3
\n" ); document.write( " \n" ); document.write( "
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