document.write( "Question 454200: Find the specific standard equation for:
\n" ); document.write( "4y^2-x^2-16y-2x+3=0
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Algebra.Com's Answer #311942 by lwsshak3(11628)\"\" \"About 
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Find the specific standard equation for:
\n" ); document.write( "4y^2-x^2-16y-2x+3=0
\n" ); document.write( "..
\n" ); document.write( "4y^2-x^2-16y-2x+3=0
\n" ); document.write( "completing the square
\n" ); document.write( "4(y^2-4y+4)-(x^2+2x+1)=-3+16-1=12
\n" ); document.write( "4(y-2)^2-(x+1)^2=12
\n" ); document.write( "Equation of conic:
\n" ); document.write( "(y-2)^2/3-(x+1)^2/12=1
\n" ); document.write( "This is a hyperbola with vertical transverse axis and center at (-1, 2)
\n" ); document.write( "See graph below as a visual check on the equation
\n" ); document.write( "..
\n" ); document.write( "y=(3+(x+1)^2/4)^.5+2\r
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