document.write( "Question 454235: Formula for an ellipse= (x+1)^24(y+3)^2=1
\n" ); document.write( "what are the vertices and foci of this ellipse
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Algebra.Com's Answer #311936 by Alan3354(69443)\"\" \"About 
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Formula for an ellipse= (x+1)^24(y+3)^2=1
\n" ); document.write( "what are the vertices and foci of this ellipse
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\n" ); document.write( "Do you mean (x+1)^2 + 4(y+3)^2=1 ?
\n" ); document.write( "(x+1)^2/1 + (y+3)^2/0.25 = 1
\n" ); document.write( "a^2 = 1, b^2 = 1/4
\n" ); document.write( "Center at (-1,-3), long axis parallel to the x-axis
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\n" ); document.write( "Distance to foci = sqrt(a^2 - b^2) = sqrt(0.75)
\n" ); document.write( "Foci at (-1-sqrt(0/75),-3) and (-1+sqrt(0.75,-3)
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\n" ); document.write( "Vertices 1 unit from center parallel to x-axis and 1/2 unit vertical
\n" ); document.write( "--> (-2,-3) and (0,-3)
\n" ); document.write( "and (-1,-3.5) and (-1,-2.5)
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