document.write( "Question 453869: a Boeing apache longbow military helicopter traveling directly into a strong headwind was able to travel 450 mi in 2.5 h. the return trip, now with a tailwind, took 1 h 40 min. find the speed of the helicopter in calm air and the rate of the wind\r
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Algebra.Com's Answer #311926 by jorel1380(3719)\"\" \"About 
You can put this solution on YOUR website!
450/2.5=180 mph
\n" ); document.write( "450/1.666=270 mph
\n" ); document.write( "180+270/2=225
\n" ); document.write( "225-180=45
\n" ); document.write( "270-225=45
\n" ); document.write( "The speed of the helicopter in calm air is 225 mph. The wind speed is 45 mph..
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