document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=453862>Question 453862</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular field having an area of 2700 m^2 is to be enclosed by a fence, and an additional fence is to be used to divide the field in the middle. The cost of the fence down the middle is $24 per running meter, and the fence along the sides cost $36 per running meter. Estimate the dimensions of the field so that the total cost of the fencing material is least.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #311913 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=311913\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A rectangular field having an area of 2700 m^2 is to be enclosed by a fence, and<BR>\n" );
document.write( " an additional fence is to be used to divide the field in the middle.<BR>\n" );
document.write( " The cost of the fence down the middle is $24 per running meter, and the fence<BR>\n" );
document.write( " along the sides cost $36 per running meter. <BR>\n" );
document.write( "Estimate the dimensions of the field so that the total cost of the fencing material is least.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "the area<BR>\n" );
document.write( "L * W = 2700<BR>\n" );
document.write( "L = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2700%2FW ALIGN=MIDDLE  ALT=\"2700%2FW\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ":<BR>\n" );
document.write( "The perimeter<BR>\n" );
document.write( "p = 2L + 2W + W; (3rd width down the middle)<BR>\n" );
document.write( "Cost = 36(2L) + 36(2W) + 24W<BR>\n" );
document.write( "C = 72L + 72W + 24W<BR>\n" );
document.write( "C = 72L + 96W<BR>\n" );
document.write( "Replace L with <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2700%2FW ALIGN=MIDDLE  ALT=\"2700%2FW\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "C = 72*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2700%2FW ALIGN=MIDDLE  ALT=\"2700%2FW\"   DISABLED_style= \"max-width:90%; height:auto;\" > + 96W<BR>\n" );
document.write( "C = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=194400%2FW ALIGN=MIDDLE  ALT=\"194400%2FW\"   DISABLED_style= \"max-width:90%; height:auto;\" > + 96W<BR>\n" );
document.write( "Graph this:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-20%2C+80%2C+-1000%2C+15000%2C+96x%2B%28194400%2Fx%29%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-20%2C+80%2C+-1000%2C+15000%2C+96x%2B%28194400%2Fx%29%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ":<BR>\n" );
document.write( "looks like min cost occurs when the width is 45 meters<BR>\n" );
document.write( "then<BR>\n" );
document.write( "length = 2700/45 = 60 meters<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "36(2*60) + 36(2*45) + 24(45) = $8640 is the min cost </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );