document.write( "Question 454170: I must have left out some information
\n" ); document.write( "I am looking to rationalize the following denominator\r
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\n" ); document.write( "\n" ); document.write( "I get as far as 6 over 3rd root 3 , but can I reduce further ? \n" ); document.write( "

Algebra.Com's Answer #311912 by Edwin McCravy(20056) $\"\"$ $\"About$

You can put this solution on YOUR website!
18 over 3rd root 81
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document.write( "Break up 81 this way\r\n" );
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document.write( "81 = 9‧9 = 3‧3‧3‧3 = 3⁴\r\n" );
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document.write( "To get rid of the 3rd root in the denominator we need \r\n" );
document.write( "an exponent of 3 which is a multiple of 3.\r\n" );
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document.write( "To get that we multiply top and bottom by  ∛3²\r\n" );
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document.write( "We multiply tops and bottoms, we multiply under the\r\n" );
document.write( "radicals on the bottom so we'll have 3⁶ under the radical\r\n" );
document.write( "which has an exponent of 6 which is a multiple of 3\r\n" );
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document.write( "Now we get rid of the radical on the bottom by\r\n" );
document.write( "dividing the power of 3 which is 6 by the index of\r\n" );
document.write( "the root which is 3 and get 3² \r\n" );
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document.write( "Then we make both 3²'s into 9\r\n" );
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document.write( "Then the 9 cancels into the 18 and gives 2 on the top\r\n" );
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document.write( "So that's the answer 2∛9\r\n" );
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document.write( "Edwin

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