document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47085>Question 47085</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I can not figure this problem out...please help me. I am not getting any one of these answers....What am I doing wrong.\r<BR>\n" );
document.write( "\n" );
document.write( "Subtract. Write your answer in simplest form.\r<BR>\n" );
document.write( "\n" );
document.write( "y-2/y+3 - y/2y+6\r<BR>\n" );
document.write( "\n" );
document.write( "Choices are:  A) y^2+y-12/(y+3)(2y+6) B) y-2/y+3 C) y-4/2(y+3) D) 3y-4/2(y+3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31190 by </B><A HREF=/tutors/aboutme.mpl?userid=mathchemprofessor><B>mathchemprofessor(65)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathchemprofessor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31190\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y-2/y+3 - y/2y+6<BR>\n" );
document.write( "LCM is (y+3)(2y+6)<BR>\n" );
document.write( "On adding both of them, we get<BR>\n" );
document.write( "((y-2)(2y+6)-y(y+3))/(y+3)(2y+6)<BR>\n" );
document.write( "=2y^2+6y-4y-12-y^2-3y/(y+3)(2y+6)( expansion of the numerator)<BR>\n" );
document.write( "=(y^2-y-12)/(y+3)(2y+6)(simplification of the numerator)<BR>\n" );
document.write( "=(y-4)(y+3)/(y+3)(2y+6)(factoring the numerator)<BR>\n" );
document.write( "=(y-4)/(2y+6) ( cancellation of the common term)<BR>\n" );
document.write( "=(y-4)/2(y+3) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );