document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=454017>Question 454017</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help and I am not sure if this is even the right section! They want us to find f(-3) When f(x)=x to the second power plus 3x-4 I am so confused I think I am supposed to plug -3 into the equation were the x value is just wanted to compare what I got to someone else. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #311831 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=311831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(-3)=-3^2+3*-3-4<BR>\n" );
document.write( "f(-3)=9-9-4<BR>\n" );
document.write( "f(-3)=-4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );