document.write( "Question 454009: I need to create a rational function with the following:
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document.write( "Crosses x-axis at 2
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document.write( "Touches the x-axis at -1
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document.write( "One verticle asymptote at x=-5 and another at x=6
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document.write( "One horizontal asymptote at y=3\r
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document.write( "help! i need to know the steps \n" );
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Algebra.Com's Answer #311823 by solver91311(24713) You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If your function crosses the \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If your function just touches the \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If the function must have a vertical asymptote at -5, then the denominator polynomial must have a zero at -5. Hence a factor of the denominator must be \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Likewise, for a vertical asymptote at 6, the denominator must have a factor of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In order for there to be a horizontal asymptote other than the \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In order to accomplish equal degree, we need to double up on one of the factors in the denominator. I choose the \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In order for there to be a 3 to 1 ratio between the lead coefficients on the numerator and denominator such that the horizontal asymptote occurs at \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Putting it all together:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can multiply the factors yourself if that is the form of the answer you are required to submit.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |