document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=450996>Question 450996</A>: <I><SPAN STYLE=\"word-break: break-all;\"> copyqwik has four photocopy machines a,b,c,d. the probability that a given machine will break down on a particular day is p(a)=1/50  p(b)= 1/60  p(c)= 1/75  p(d)= 1/50.  Assuming independance what is the probability on a particular day that all 4 machines will break down? and none will break down? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #311815 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=311815\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Probability that all 4 are broken down:1/50x1/60x1/75x1/50=1/11250000.<BR>\n" );
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document.write( "Probability that none will break down=49/50x59/60x74/75x49/50=10482766/11250000.. </SPAN>\n" );
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