document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=453968>Question 453968</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of infinite geometric series with first term 3 and second term 0.75 is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #311810 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=311810\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of the series is given by:<BR>\n" );
document.write( "S = a/(1-r) where a = the 1st term in the series and r = the common ratio<BR>\n" );
document.write( "r = 0.75/3 = 0.25<BR>\n" );
document.write( "So S= 3/0.75 = 4 </SPAN>\n" );
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