document.write( "Question 453903: Hi,
\n" ); document.write( "Solve: \"5-4x+%3E=+15%2B3x\"\r
\n" ); document.write( "\n" ); document.write( "Thanks :)
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Algebra.Com's Answer #311774 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
5-4x >= 15+3x
\n" ); document.write( "Add 4x to both sides to get:
\n" ); document.write( "5 >= 17+7x
\n" ); document.write( "---
\n" ); document.write( "Subtract 17 from both sides to get:
\n" ); document.write( "-12 >= 7x
\n" ); document.write( "---
\n" ); document.write( "Divide both sides by 7 to get:
\n" ); document.write( "x <= -12/7
\n" ); document.write( "=====================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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