document.write( "Question 453840: Solve, giving all solutions between 0 and 360 degrees:\r
\n" ); document.write( "\n" ); document.write( "\"cot%28z%2F2%29\" - \"2cos%28z%2F2%29\" = 0
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Algebra.Com's Answer #311760 by poliphob3.14(115)\"\" \"About 
You can put this solution on YOUR website!
First we simplify the equation:\"cos%28z%2F2%29%2Fsin%28z%2F2%29-2cos%28z%2F2%29=0\", multiply both \r
\n" ); document.write( "\n" ); document.write( "sides by \"sin%28z%2F2%29\" and get:\"cos%28z%2F2%29-2sin%28z%2F2%29%2Acos%28z%2F2%29=0\", factor \r
\n" ); document.write( "\n" ); document.write( "further, \"cos%28z%2F2%29%281-2sin%28z%2F2%29%29=0\". This product will be zero if:\r
\n" ); document.write( "\n" ); document.write( "\"cos%28z%2F2%29=0\" or \"1-2sin%28z%2F2%29=0\". Solving these two equivalent equations \r
\n" ); document.write( "\n" ); document.write( "we find:1)\"cos%28z%2F2%29=0\"=>\"z%2F2=%28pi%29%2F2\"=>\"z=pi\" and \"z%2F2=3%2Api%2F2\"=>\r
\n" ); document.write( "\n" ); document.write( "\"z=3%2Api\".\r
\n" ); document.write( "\n" ); document.write( "2)\"1-2si%28z%2F2%29=0\"=>\"sin%28z%2F2%29=1%2F2\"=>\"z%2F2=pi%2F6\"=>\"z=pi%2F3\" and,\r
\n" ); document.write( "\n" ); document.write( "\"z%2F2=5%2Api%2F6\"=>\"z=5%2Api%2F3\"
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