document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=453861>Question 453861</A>: <I><SPAN STYLE=\"word-break: break-all;\"> car A and car B travel from town to a vacation cabin. car A travels at 45 mph. car B leaves two hours after car A and travels 15 mph faster than car A. if the cars arrive at the same time, how many miles is it from town to the cabin </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #311743 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=311743\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> time car A - time car B = 2 hours\r<BR>\n" );
document.write( "\n" );
document.write( "Let distance to cabin be x<BR>\n" );
document.write( "car A speed = 45<BR>\n" );
document.write( "Car B speed = 45+15=60 mph<BR>\n" );
document.write( "x/45 -x/60=2<BR>\n" );
document.write( "LCD = 180<BR>\n" );
document.write( "4x-3x= 2*180<BR>\n" );
document.write( "x=360<BR>\n" );
document.write( "x=360 miles<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );