document.write( "Question 453837: how do you graph y^2-x^2=9 \n" ); document.write( "
Algebra.Com's Answer #311740 by lwsshak3(11628)\"\" \"About 
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how do you graph y^2-x^2=9
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\n" ); document.write( "Standard form of a hyperbola with horizontal transverse axis: (x-h)^2/a^2-(y-k)^2/b^2=1, with (h,k) being the (x,y) coordinates of the center.
\n" ); document.write( "Standard form of a hyperbola with vertical transverse axis: (y-k)^2/a^2-(x-h)^2/b^2=1, with (h,k) being the (x,y) coordinates of the center.
\n" ); document.write( "The difference between the two forms is the interchange of (x-h) and (y-k)
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\n" ); document.write( "y^2-x^2=9
\n" ); document.write( "y^2/9-x^2/9=1
\n" ); document.write( "Given equation is a hyperbola with center at (0, 0) and it has a vertical transverse axis.
\n" ); document.write( "a^2=9
\n" ); document.write( "a=3
\n" ); document.write( "2a=6=transverse axis
\n" ); document.write( "vertices: (0,0±3)
\n" ); document.write( "b^2=9
\n" ); document.write( "b=3
\n" ); document.write( "2b=6=conjugate axis
\n" ); document.write( "Equation of asymptotes: y=±(a/b)x
\n" ); document.write( "See the graph below as a visual check
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\n" ); document.write( "y=(9+x^2)^.5
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