document.write( "Question 451136: Solve: 25^log5^x=5 \n" ); document.write( "
Algebra.Com's Answer #311739 by lwsshak3(11628)\"\" \"About 
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Solve: 25^log5^x=5
\n" ); document.write( "..
\n" ); document.write( "25^log5^x=5
\n" ); document.write( "25=5^2
\n" ); document.write( "5^2^log5^x=5
\n" ); document.write( "5^2log5^x=5^1
\n" ); document.write( "2log5^x=1
\n" ); document.write( "log5^x=1/2
\n" ); document.write( "convert to exponential form, (base(10) raised to log of number(1/2)=number(5^x)
\n" ); document.write( "10^(1/2)=5^x
\n" ); document.write( "3.1623=5^x
\n" ); document.write( "(take logs of both sides)
\n" ); document.write( "xlog5=log(3.1623)
\n" ); document.write( "x=log(3.1623)/log5
\n" ); document.write( "x=.7153
\n" ); document.write( "..
\n" ); document.write( "Check:
\n" ); document.write( "25^log5^x
\n" ); document.write( "25^log5^.7153=4.999... \n" ); document.write( "
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