document.write( "Question 450339: What is the solution to 2*2^x+1 -5=15 \n" ); document.write( "
Algebra.Com's Answer #311738 by lwsshak3(11628)\"\" \"About 
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What is the solution to 2*2^(x+1) -5=15
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\n" ); document.write( "2*2^(x+1) -5=15
\n" ); document.write( "2*2^(x+1) =20
\n" ); document.write( "2^(x+1)=20/2=10
\n" ); document.write( "(x+1) log2=log 10=1
\n" ); document.write( "xlog2+log2=1
\n" ); document.write( "xlog2=1-log2
\n" ); document.write( "x=(1-log2)/log2
\n" ); document.write( "x=2.3219 (ans)
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\n" ); document.write( "Check
\n" ); document.write( "2*2^(x+1) -5
\n" ); document.write( "2*2^(2.3219+1)-5
\n" ); document.write( "2*2^(3.3219)-5=14.999.. \n" ); document.write( "
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