document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47017>Question 47017</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve:<BR>\n" );
document.write( "2y(y+4)=-5(y+3)<BR>\n" );
document.write( "2y(y+4)-5(y+3)=0<BR>\n" );
document.write( "unclear as to where to take it from there.<BR>\n" );
document.write( "I don't see how they got -3/2,5 out of that. I'm trying though. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31165 by </B><A HREF=/tutors/aboutme.mpl?userid=uuuu><B>uuuu(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uuuu><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31165\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use the quadratic formula for the problem 2y^2+3y-15=0 <BR>\n" );
document.write( "I might be a little off since im doing this in my head but you should get close to or exactly y=-3/4-1/4 square root of 129 and y=-3/4+1/4 square root of 129 if you need to see the steps if youre still not getting it email me back  </SPAN>\n" );
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