document.write( "Question 453376: i wasn't sure what to put this under but my question is:
\n" ); document.write( "3^x=2 and you need to solve for x. thanks in advance
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Algebra.Com's Answer #311623 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
3^x=2 and you need to solve for x.
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\n" ); document.write( "Using common logs
\n" ); document.write( "log(3^x) = log(2)
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\n" ); document.write( "the log equiv of exponents
\n" ); document.write( "x*log(3) = log(2)
\n" ); document.write( "x = \"log%282%29%2FLog%283%29\"
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\n" ); document.write( "using a calc
\n" ); document.write( "x = .63093, (you will get the same solution using natural logs)
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\n" ); document.write( ":
\n" ); document.write( "Check this on calc: enter 3^.63093, results: 2.000
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