document.write( "Question 453376: i wasn't sure what to put this under but my question is:
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document.write( "3^x=2 and you need to solve for x. thanks in advance \n" );
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Algebra.Com's Answer #311623 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! 3^x=2 and you need to solve for x. \n" ); document.write( "; \n" ); document.write( "Using common logs \n" ); document.write( "log(3^x) = log(2) \n" ); document.write( ": \n" ); document.write( "the log equiv of exponents \n" ); document.write( "x*log(3) = log(2) \n" ); document.write( "x = \n" ); document.write( ": \n" ); document.write( "using a calc \n" ); document.write( "x = .63093, (you will get the same solution using natural logs) \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check this on calc: enter 3^.63093, results: 2.000 \n" ); document.write( " |