document.write( "Question 453513: a car travels from A to B, a distance of 210 miles at 30 mph.Another car travels from B to A one hour afterwards with speed of 70 mph.A what point they cross.if the first car left at 10:00 hours, what is the time of their crossing. \n" ); document.write( "
Algebra.Com's Answer #311613 by ankor@dixie-net.com(22740)\"\" \"About 
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A car travels from A to B, a distance of 210 miles at 30 mph.
\n" ); document.write( "Another car travels from B to A one hour after-wards, with speed of 70 mph.
\n" ); document.write( " At what point they cross, if the first car left at 10:00 hours?
\n" ); document.write( "What is the time of their crossing?
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\n" ); document.write( "Summarize:
\n" ); document.write( "Car 1: A to B, 210 mi, 30 mph, left at 10:00
\n" ); document.write( "Car 2: B to A, 210 mi, 70 mph, left at 11:00
\n" ); document.write( ":
\n" ); document.write( "Let t = A's travel time when they meet
\n" ); document.write( "then
\n" ); document.write( "(t-1) = B's travel time when they meet
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation, Dist = speed * time
\n" ); document.write( "Car 1 dist + Car 2 dist = 210 mi
\n" ); document.write( "30t + 70(t-1) = 210
\n" ); document.write( "30t + 70t - 70 = 210
\n" ); document.write( "100t = 210 + 70
\n" ); document.write( "100t = 280
\n" ); document.write( "t = \"280%2F100\"
\n" ); document.write( "t = 2.8 hrs, travel time of car 1 (left at 10 am)
\n" ); document.write( "Convert hrs min: 2 + .8(60) 2 hrs 48 min
\n" ); document.write( "10:00 + 2:48 = 12:48 PM when they meet
\n" ); document.write( ":
\n" ); document.write( "Find the distance from A when they meet:
\n" ); document.write( "30 * 2.8 = 84 mi from A
\n" ); document.write( "Check this by finding the dist from B, using Car 2
\n" ); document.write( "70 * 1.8 = 126 mi from B
\n" ); document.write( "Check this find the total: 84 + 126 = 210 mi
\n" ); document.write( ":
\n" ); document.write( "Summarize, Car 1 meets Car 2, 84 mi from town A at 12:48 PM
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