document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=453477>Question 453477</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the triangle KLM the length of KM is approximately what?: (Round to the nearest tenth)<BR>\n" );
document.write( "KL= 7in<BR>\n" );
document.write( "Angle M= 110 degrees<BR>\n" );
document.write( "Angle L=30 degrees </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #311579 by </B><A HREF=/tutors/aboutme.mpl?userid=pedjajov><B>pedjajov(51)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pedjajov><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=311579\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If we draw a height (h) from vertex M it forms two right triangles LNM and KNM where N is a point where height h intersects KL.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "It also divides KL into two pieces x=KN and y=LN:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2By=7 ALIGN=MIDDLE  ALT=\"x%2By=7\"   DISABLED_style= \"max-width:90%; height:auto;\" > -> x=7-y<BR>\n" );
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document.write( "Knowing that angle L=30 and angle M=110, it makes angle K=40.<BR>\n" );
document.write( "Now we have:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%2830%29=h%2Fy ALIGN=MIDDLE  ALT=\"tan%2830%29=h%2Fy\"   DISABLED_style= \"max-width:90%; height:auto;\" > -> h=tan(30)*y<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%2840%29=h%2Fx ALIGN=MIDDLE  ALT=\"tan%2840%29=h%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" > -> h=tan(40)*x<BR>\n" );
document.write( ":<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%2840%29%2Ax=tan%2830%29%2Ay ALIGN=MIDDLE  ALT=\"tan%2840%29%2Ax=tan%2830%29%2Ay\"   DISABLED_style= \"max-width:90%; height:auto;\" >, substitute x with 7-y<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%2840%29%2A%287-y%29=tan%2830%29%2Ay ALIGN=MIDDLE  ALT=\"tan%2840%29%2A%287-y%29=tan%2830%29%2Ay\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%2840%29%2A7-tan%2840%29%2Ay=tan%2830%29%2Ay ALIGN=MIDDLE  ALT=\"tan%2840%29%2A7-tan%2840%29%2Ay=tan%2830%29%2Ay\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=7%2Atan%2840%29%2F%28tan%2830%29%2Btan%2840%29%29 ALIGN=MIDDLE  ALT=\"y=7%2Atan%2840%29%2F%28tan%2830%29%2Btan%2840%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "y=4.1<BR>\n" );
document.write( ":<BR>\n" );
document.write( "x=7-y -> x=7-4.1 -> x=2.9<BR>\n" );
document.write( ":<BR>\n" );
document.write( "We can find KM knowing that:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cos%2840%29=x%2FKM ALIGN=MIDDLE  ALT=\"cos%2840%29=x%2FKM\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=KM=x%2Fcos%2840%29 ALIGN=MIDDLE  ALT=\"KM=x%2Fcos%2840%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "KM=3.8\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
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