document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=453484>Question 453484</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars start from towns 840 miles apart and travel toward each other. They meet after 7 hours. Find the speed of each car if one travels 10mph faster than the other. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #311560 by </B><A HREF=/tutors/aboutme.mpl?userid=pedjajov><B>pedjajov(51)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pedjajov><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=311560\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Each car travels r*t miles where:<BR>\n" );
document.write( "r - speed of the car<BR>\n" );
document.write( "t - time it travels<BR>\n" );
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document.write( "If first car travels with speed r, then the other one travels with speed r+10.<BR>\n" );
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document.write( "After 7 hours first car travels 7r miles, while other one travels 7(r+10) miles.<BR>\n" );
document.write( "Together they travel 840 miles.<BR>\n" );
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document.write( "7r+7(r+10)=840, divide by 7<BR>\n" );
document.write( "r+r+10=840, combine like terms<BR>\n" );
document.write( "2r+10=120, subtract 10<BR>\n" );
document.write( "2r=110, divide by 2<BR>\n" );
document.write( "r=55<BR>\n" );
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document.write( "First car travels with speed of 55 mph, while the other one travels 65mph.<BR>\n" );
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