document.write( "Question 47009: geometry problems:\r
\n" ); document.write( "\n" ); document.write( " I'm uncertain as how to set these up.\r
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\n" ); document.write( "\n" ); document.write( "the length of a rectangle is two feet more than twice the width.
\n" ); document.write( "the area is 144ft^2. find the length and the width of the rectangle.
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Algebra.Com's Answer #31152 by venugopalramana(3286)\"\" \"About 
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the length=L SAY of a rectangle is two feet more than twice the width=W SAY.
\n" ); document.write( "the area is 144ft^2. find the length and the width of the rectangle.
\n" ); document.write( "TWICE WIDTH =2W
\n" ); document.write( "2 FEET MORE =2W+2=2(W+1)
\n" ); document.write( "L=2W+2
\n" ); document.write( "AREA=A=L*W=2(W+1)W=144
\n" ); document.write( "W(W+1)=144/2=72
\n" ); document.write( "W^2+W-72=0
\n" ); document.write( "W^2+9W-8W-72=0
\n" ); document.write( "W(W+9)-8(W+9)=0
\n" ); document.write( "(W-8)(W+9)=0
\n" ); document.write( "W=8
\n" ); document.write( "L=2(8+1)=18
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