document.write( "Question 47009: geometry problems:\r
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document.write( " I'm uncertain as how to set these up.\r
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document.write( "the length of a rectangle is two feet more than twice the width.
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document.write( "the area is 144ft^2. find the length and the width of the rectangle. \n" );
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Algebra.Com's Answer #31152 by venugopalramana(3286) You can put this solution on YOUR website! the length=L SAY of a rectangle is two feet more than twice the width=W SAY. \n" ); document.write( "the area is 144ft^2. find the length and the width of the rectangle. \n" ); document.write( "TWICE WIDTH =2W \n" ); document.write( "2 FEET MORE =2W+2=2(W+1) \n" ); document.write( "L=2W+2 \n" ); document.write( "AREA=A=L*W=2(W+1)W=144 \n" ); document.write( "W(W+1)=144/2=72 \n" ); document.write( "W^2+W-72=0 \n" ); document.write( "W^2+9W-8W-72=0 \n" ); document.write( "W(W+9)-8(W+9)=0 \n" ); document.write( "(W-8)(W+9)=0 \n" ); document.write( "W=8 \n" ); document.write( "L=2(8+1)=18 \n" ); document.write( " |