document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=453287>Question 453287</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find a two-decimal-place number between 0 and one such that the  sum of its digits is 9 and such that if the digits are reversed the number is increased by 0.27 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #311505 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=311505\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The number is 0.36.\r<BR>\n" );
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document.write( "Let x be the tens place, y the ones place.\r<BR>\n" );
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document.write( "Then x + y = 9, and 10x + y + 27 = 10y + x\r<BR>\n" );
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document.write( "==> 27 = 9y - 9x <==> y - x = 3\r<BR>\n" );
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document.write( "y - x = 3<BR>\n" );
document.write( "y + x = 9\r<BR>\n" );
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document.write( "==> 2y = 12<BR>\n" );
document.write( "y = 6 ==> x = 3.\r<BR>\n" );
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document.write( "The decimal number is 0.36.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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