document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=453332>Question 453332</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I don't know where to go so that's why I came here.<BR>\n" );
document.write( "The current I in an electrical conductor varies inversely as the resistance R of the conductor. The current is 9 amperes when the when the resistance is 920 ohms. What is the current when the resistance is 560 ohms.<BR>\n" );
document.write( "Preciate it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #311483 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=311483\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use E=IR<BR>\n" );
document.write( "E=9*920<BR>\n" );
document.write( "E=8280 volts<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "I=E/R<BR>\n" );
document.write( "I=8280/560<BR>\n" );
document.write( "I=14.8 Amps<BR>\n" );
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document.write( "Bob Certified Electronic Technician </SPAN>\n" );
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