document.write( "Question 453203: An airplane is flying at a velocity of 450 mph due east when it encounters a wind blowing from the southwest at 35 mph.\r
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document.write( "-What is the the planes velocity relative to the ground?
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document.write( "- In what direction is it flying as a result of the wind? \n" );
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Algebra.Com's Answer #311413 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Due east is 090 degrees. \n" ); document.write( "From the southwest is a wind from 225 degrees. \n" ); document.write( "----------- \n" ); document.write( "The vector of the plane is 450 to the right. \n" ); document.write( "The wind is magnitude 35 at an angle of 135 degs from the plane's vector. \n" ); document.write( "The plane's ground speed = \n" ); document.write( "=~ 483.89 mph \n" ); document.write( "--------------- \n" ); document.write( "Use the Law of Sines to find the angle between 090 and the ground track \n" ); document.write( "483.89/sin(135) = 35/sin(A) \n" ); document.write( "sin(A) = 35*sin(135)/483.89 \n" ); document.write( "sin(A) = 0.051145 \n" ); document.write( "A = 2.93 degs \n" ); document.write( "Heading = 090 - A = 087.07 degs \n" ); document.write( "= 087 to the nearest degree \n" ); document.write( " \n" ); document.write( " |