document.write( "Question 453203: An airplane is flying at a velocity of 450 mph due east when it encounters a wind blowing from the southwest at 35 mph.\r
\n" ); document.write( "\n" ); document.write( "-What is the the planes velocity relative to the ground?
\n" ); document.write( "- In what direction is it flying as a result of the wind?
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Algebra.Com's Answer #311413 by Alan3354(69443)\"\" \"About 
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Due east is 090 degrees.
\n" ); document.write( "From the southwest is a wind from 225 degrees.
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\n" ); document.write( "The vector of the plane is 450 to the right.
\n" ); document.write( "The wind is magnitude 35 at an angle of 135 degs from the plane's vector.
\n" ); document.write( "The plane's ground speed = \"sqrt%28450%5E2+%2B+35%5E2+-+2%2A450%2A35%2Acos%28135%29%29\"
\n" ); document.write( "=~ 483.89 mph
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\n" ); document.write( "Use the Law of Sines to find the angle between 090 and the ground track
\n" ); document.write( "483.89/sin(135) = 35/sin(A)
\n" ); document.write( "sin(A) = 35*sin(135)/483.89
\n" ); document.write( "sin(A) = 0.051145
\n" ); document.write( "A = 2.93 degs
\n" ); document.write( "Heading = 090 - A = 087.07 degs
\n" ); document.write( "= 087 to the nearest degree
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