document.write( "Question 47008: The lenght of a rectangle is 2 in. more than 8 times its width. If the area of the rectangle is 210 sq.in, find the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #31141 by Nate(3500) $\"\"$ $\"About$

You can put this solution on YOUR website!
width = w
\n" ); document.write( "length = 8w + 2
\n" ); document.write( " $\"AREA+=+lw\"$
\n" ); document.write( " $\"210+=+8w%5E2+%2B+2w\"$
\n" ); document.write( " $\"0+=+8w%5E2+%2B+2w+-+210\"$
\n" ); document.write( " $\"0+=+4w%5E2+%2B+w+-+105\"$
\n" ); document.write( " $\"0+=+4w%5E2+%2B+21w+-+20w+-+105\"$
\n" ); document.write( " $\"0+=+%284w%5E2+%2B+21w%29+%2B+%28-20w+-+105%29\"$
\n" ); document.write( " $\"0+=+w%284w+%2B+21%29+-+5%284w+%2B+21%29\"$
\n" ); document.write( " $\"0+=+%28w+-+5%29%284w+%2B+21%29\"$
\n" ); document.write( "Since a measure ment can not be negative, your width is:
\n" ); document.write( "w - 5 = 0
\n" ); document.write( "w = 5
\n" ); document.write( "length = 8w + 2 = 42 \n" ); document.write( "

\n" );