document.write( "Question 453181: Five years from now, a father's age will be three times his son's age, and five years ago, he was seven times as old as his son was. What are their present ages? \n" ); document.write( "
Algebra.Com's Answer #311391 by stanbon(75887)\"\" \"About 
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Five years from now, a father's age will be three times his son's age, and five years ago, he was seven times as old as his son was. What are their present ages?
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\n" ); document.write( "Equation(s):
\n" ); document.write( "(f+5) = 3(s+5)
\n" ); document.write( "(f-7) = 7(s-7)
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\n" ); document.write( "Rearrange:
\n" ); document.write( "f - 3s = 10
\n" ); document.write( "f - 7s = -42
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\n" ); document.write( "Subtract and solve for \"s\":
\n" ); document.write( "4s = 52
\n" ); document.write( "s = 13 (son's age now)
\n" ); document.write( "---
\n" ); document.write( "Solve for \"f\":
\n" ); document.write( "f -3s = 10
\n" ); document.write( "f - 39 = 10
\n" ); document.write( "f = 49 (father's age now)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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