document.write( "Question 453142: The perimeter of a rectangle is 240 ft. The length is 2 ft greater than the width. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #311376 by pedjajov(51)![]() ![]() ![]() You can put this solution on YOUR website! Perimeter of the rectangle is given as: \n" ); document.write( ": \n" ); document.write( "P=2(w+l) \n" ); document.write( ": \n" ); document.write( "Relationship between width and the length is given as: \n" ); document.write( ": \n" ); document.write( "l=w+2 \n" ); document.write( ": \n" ); document.write( "Substitute l in formula for P: \n" ); document.write( "P=2(w+w+2) \n" ); document.write( "P=2(2w+2) \n" ); document.write( "P=4w+4 \n" ); document.write( ": \n" ); document.write( "240=4w+4 \n" ); document.write( "4w=236 \n" ); document.write( "w=59, this is width in ft. \n" ); document.write( ": \n" ); document.write( "l=w+2 \n" ); document.write( "l=59+2 \n" ); document.write( "l=61, this is length in ft. \n" ); document.write( " |