document.write( "Question 453104: In 2009, Beaver Hospital admitted 14,800 patients. In 2010, a 20% increase in admissions is expected. Assume the hospital has 390 beds.
\n" ); document.write( "a) If the average patient stays in the hospital 8 days, how many beds were empty, on average, in 2009?\r
\n" ); document.write( "\n" ); document.write( "b) On average, how many beds do you expect to be empty in 2010?\r
\n" ); document.write( "\n" ); document.write( "I'm not sure how to begin in setting up the problem or solving it. Please help with the set-up and solution. Thanks so much. \n" ); document.write( "

Algebra.Com's Answer #311329 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "14800 divided by 365 is roughly 40.5. So, you can presume, on average, that 40.5 people get admitted on any given day, and then 40.5 people the next day, and so on. But after 8 days, on average, 40.5 people go home. So at any given time in the year 2009 there are 8 times 40.5, roughly 244 people, in the hospital at any given time. 390 minus 244 is 146 empty beds.\r
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\n" ); document.write( "\n" ); document.write( "If you increase admissions by 20 percent you increase the occupancy by 20 percent. 1.2 times 244 rounds to 293 (presuming you would never have a fraction of a person) hence the empties have been reduced to 97 in the year 2010.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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$\"The$

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