document.write( "Question 453011: can someone help me by tuesday plss :(?
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document.write( "solve the problem.\r
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document.write( "the speed of the freight train is 18 km/h slower than the speed of a passenger train. the freight train travels 209 km in the same time that it takes the passenger train to travel 308 km. find the speed of each train. \n" );
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Algebra.Com's Answer #311249 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Freight train x ---- 209 miles \n" ); document.write( "Passanger Train x+18------ 308 miles \n" ); document.write( " \n" ); document.write( "t=d/r \n" ); document.write( "209/x=308/(x+18) \n" ); document.write( "Cross multiply \n" ); document.write( "209(x+18)=308*x \n" ); document.write( "209x+3762=308x \n" ); document.write( "308x-209x=3762 \n" ); document.write( "99x=3762 \n" ); document.write( "/99 \n" ); document.write( "x=38 Freight train mph \n" ); document.write( "38+18===>56 Passanger Train mph \n" ); document.write( " \n" ); document.write( " |