document.write( "Question 452984: The total cost(in dollars) for a company to manufacture and sell x items per week is C=60x+300, where as the revenue brought in selling all x items is R=100x-0.5x^2 . How many items must be sold to obtain a weekly profit of $300?
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Algebra.Com's Answer #311246 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Profit is (revenue - cost)
\n" ); document.write( "\"R+=+100x+-+.5x%5E2%0D%0A%7B%7B%7BC+=+60x+%2B+300+\"
\n" ); document.write( "\"+R+-+C+=+100x+-+.5x%5E2+-+60x+-+300+\"
\n" ); document.write( "\"+P+=+-+.5x%5E2+%2B+40x+-+300+\"
\n" ); document.write( "\"+300+=+-+.5x%5E2+%2B+40x+-+300+\"
\n" ); document.write( "\"+-+.5x%5E2+%2B+40x+-+600+=+0+\"
\n" ); document.write( "\"+-+5x%5E2+%2B+400x+-+6000+=+0+\"
\n" ); document.write( "\"+-+x%5E2+%2B+80x+-+1200+=+0+\"
\n" ); document.write( "\"+x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"+a+=+-1+\"
\n" ); document.write( "\"+b+=+80+\"
\n" ); document.write( "\"+c+=+-1200+\"
\n" ); document.write( "\"x+=+%28-80+%2B-+sqrt%28+80%5E2+-+4%2A%28-1%29%2A%28-1200%29+%29%29%2F%282%2A%28-1%29%29+\"
\n" ); document.write( "\"x+=+%28-80+%2B-+sqrt%28+6400+-+4800+%29%29%2F%28%28-2%29%29+\"
\n" ); document.write( "\"x+=+%28-80+%2B-+sqrt%28+1600+%29%29%2F%28%28-2%29%29+\"
\n" ); document.write( "\"x+=+%28-80+%2B+40%29%2F%28%28-2%29%29+\"
\n" ); document.write( "\"+x+=+20+\"
\n" ); document.write( "and, using the negative root
\n" ); document.write( "\"x+=+%28-80+-+40%29%2F%28%28-2%29%29+\"
\n" ); document.write( "\"+x+=+60+\"
\n" ); document.write( "Selling either 20 or 60 items per week will
\n" ); document.write( "give a profit of $300
\n" ); document.write( "Here's a graph of solutions and the profit curve:
\n" ); document.write( "\"+graph%28+400%2C+400%2C+-50%2C+70%2C+-50%2C+500%2C+-x%5E2+%2B+80x+-+1200%29+\"
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