document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=452926>Question 452926</A>: <I><SPAN STYLE=\"word-break: break-all;\"> parabola with foci at (4,6) and directrix at x=8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #311240 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=311240\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Under the given conditions, the vertex will be at the point (6,6). a = 6 - 4 = 2, and the standard equation would be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2A2%28x-6%29+=+%28y+-+6%29%5E2 ALIGN=MIDDLE  ALT=\"4%2A2%28x-6%29+=+%28y+-+6%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8%28x+-+6%29+=+%28y+-+6%29%5E2 ALIGN=MIDDLE  ALT=\"8%28x+-+6%29+=+%28y+-+6%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );