document.write( "Question 452927: Using the 5-step method to solve:\r
\n" ); document.write( "\n" ); document.write( "A sailboat travels 20 miles downstream in 4 hours. It returns in 5 hours. Find the speed of the sailboat in still water and the rate of the current.
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Algebra.Com's Answer #311237 by mananth(16946)\"\" \"About 
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boat speed = x
\n" ); document.write( "current speed = y
\n" ); document.write( "..
\n" ); document.write( "distance = 20 miles
\n" ); document.write( "time = d/r\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "downstream speed = 20/(x+y)
\n" ); document.write( "upstream speed = 20/(x-y)
\n" ); document.write( "..
\n" ); document.write( "20/(x+y)=4
\n" ); document.write( "4x+4y=20
\n" ); document.write( "/4
\n" ); document.write( "x+y=5...............1
\n" ); document.write( "20/(x-y)=5
\n" ); document.write( "5x-5y=20
\n" ); document.write( "/5
\n" ); document.write( "x-y=4...............2\r
\n" ); document.write( "\n" ); document.write( "1 x + 1 y = 5 .............1
\n" ); document.write( "1 x + -1 y = 4 .............2
\n" ); document.write( "Add the two equations
\n" ); document.write( "2 x = 9
\n" ); document.write( "/ 2
\n" ); document.write( "x = 4.50
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "1 x + 1 y = 5
\n" ); document.write( "4.5 + 1 y = 5
\n" ); document.write( " 1 y = 5 -4.5
\n" ); document.write( " 1 y = 0.5
\n" ); document.write( " y = 0.50
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