document.write( "Question 452927: Using the 5-step method to solve:\r
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document.write( "A sailboat travels 20 miles downstream in 4 hours. It returns in 5 hours. Find the speed of the sailboat in still water and the rate of the current. \n" );
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Algebra.Com's Answer #311237 by mananth(16946)![]() ![]() You can put this solution on YOUR website! boat speed = x \n" ); document.write( "current speed = y \n" ); document.write( ".. \n" ); document.write( "distance = 20 miles \n" ); document.write( "time = d/r\r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "downstream speed = 20/(x+y) \n" ); document.write( "upstream speed = 20/(x-y) \n" ); document.write( ".. \n" ); document.write( "20/(x+y)=4 \n" ); document.write( "4x+4y=20 \n" ); document.write( "/4 \n" ); document.write( "x+y=5...............1 \n" ); document.write( "20/(x-y)=5 \n" ); document.write( "5x-5y=20 \n" ); document.write( "/5 \n" ); document.write( "x-y=4...............2\r \n" ); document.write( "\n" ); document.write( "1 x + 1 y = 5 .............1 \n" ); document.write( "1 x + -1 y = 4 .............2 \n" ); document.write( "Add the two equations \n" ); document.write( "2 x = 9 \n" ); document.write( "/ 2 \n" ); document.write( "x = 4.50 \n" ); document.write( "plug value of x in (1) \n" ); document.write( "1 x + 1 y = 5 \n" ); document.write( "4.5 + 1 y = 5 \n" ); document.write( " 1 y = 5 -4.5 \n" ); document.write( " 1 y = 0.5 \n" ); document.write( " y = 0.50 \n" ); document.write( " \n" ); document.write( " |