document.write( "Question 452782: a girl blends coffee for a coffee shop she needs to prepare 200 pounds of blended coffee beans, selling for $4.49 per pound. she plans to do this by blending together a high quality bean, costing $5.50 per pound and a cheaper bean at $3.25 per pound. to the nearest pound find how much high quality coffee bean and how much cheaper coffee bean she should blend \n" ); document.write( "

Algebra.Com's Answer #311225 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
needs to prepare 200 pounds of blended coffee beans, selling for $4.49 per pound.
\n" ); document.write( "do this by blending together a high quality bean, costing $5.50 per pound and a cheaper bean at $3.25 per pound.
\n" ); document.write( ":
\n" ); document.write( "Let x = amt of 5.50 per lb coffee
\n" ); document.write( "then
\n" ); document.write( "(200-x) = amt of 3.25 per lb coffee
\n" ); document.write( ";
\n" ); document.write( "5.50x + 3.25(200-x) = 4.49(200)
\n" ); document.write( ":
\n" ); document.write( "5.5x + 650 - 3.25x = 898
\n" ); document.write( ":
\n" ); document.write( "5.5x - 3.25x = 898 - 650
\n" ); document.write( ":
\n" ); document.write( "2.25x = 248
\n" ); document.write( "x = $\"248%2F2.25\"$
\n" ); document.write( "x = 110.222 ~ 110 lb of $5.50 coffee
\n" ); document.write( "and
\n" ); document.write( "200 - 110.222 = 89.77 ~ 90 lb of $3.25 coffee \n" ); document.write( "

\n" );