document.write( "Question 452761: what is the distance between 5,-2 and -3,4? \n" ); document.write( "
Algebra.Com's Answer #311183 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Note: is the first point . So this means that \"x%5B1%5D=5\" and \"y%5B1%5D=-2\".\r
\n" ); document.write( "\n" ); document.write( "Also, is the second point . So this means that \"x%5B2%5D=-3\" and \"y%5B2%5D=4\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" Start with the distance formula.\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%285--3%29%5E2%2B%28-2-4%29%5E2%29\" Plug in \"x%5B1%5D=5\", \"x%5B2%5D=-3\", \"y%5B1%5D=-2\", and \"y%5B2%5D=4\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%288%29%5E2%2B%28-2-4%29%5E2%29\" Subtract \"-3\" from \"5\" to get \"8\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%288%29%5E2%2B%28-6%29%5E2%29\" Subtract \"4\" from \"-2\" to get \"-6\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2864%2B%28-6%29%5E2%29\" Square \"8\" to get \"64\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2864%2B36%29\" Square \"-6\" to get \"36\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28100%29\" Add \"64\" to \"36\" to get \"100\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=10\" Take the square root of \"100\" to get \"10\".\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"d=10\" \r
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\n" ); document.write( "\n" ); document.write( "So the distance between the two points is 10 units.
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