document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=452737>Question 452737</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A lot is in the shape of a right triangle. The shorter leg measures 180 m. The hypotenuse is 60 m<BR>\n" );
document.write( "longer than the length of the longer leg. How long is the longer leg? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #311149 by </B><A HREF=/tutors/aboutme.mpl?userid=ilana><B>ilana(307)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ilana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=311149\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Say the length of the longer leg is x. Then the hypotenuse measures x + 60. So, using the Pythagorean Theorem, x^2 + 180^2 = (x + 60)^2.<BR>\n" );
document.write( "x^2 + 32400 = x^2 + 120x + 3600<BR>\n" );
document.write( "32400 = 120x + 3600<BR>\n" );
document.write( "120x = 28800<BR>\n" );
document.write( "x = 240<BR>\n" );
document.write( "The longer leg measures 240 m. </SPAN>\n" );
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