document.write( "Question 452573: The line of sight from a small boat to the light at the top of a 45-foot lighthouse built on a cliff 25 feet above the water makes a 39 degree angle with the water. To the nearest foot, how far is the boat from the cliff? \n" ); document.write( "
Algebra.Com's Answer #311148 by ankor@dixie-net.com(22740)\"\" \"About 
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The line of sight from a small boat to the light at the top of a 45-foot
\n" ); document.write( " lighthouse built on a cliff 25 feet above the water makes a 39 degree angle with the water.
\n" ); document.write( "To the nearest foot, how far is the boat from the cliff?
\n" ); document.write( ":
\n" ); document.write( "Let d = distance to the base of the cliff (side adjacent to 39 degree angle)
\n" ); document.write( "25 + 45 = 70'; height of lighthouse, side opposite 39 degree angle
\n" ); document.write( ":
\n" ); document.write( "Tan(39) = \"70%2Fd\"
\n" ); document.write( "d = \"70%2Ftan%2839%29\"
\n" ); document.write( "d = 86 ft from the base of the cliff
\n" ); document.write( ":
\n" ); document.write( "Distance from the boat to the cliff (c) itself which is 25' ft above the base, use pythag
\n" ); document.write( "c^2 = 25^2 + 86^2
\n" ); document.write( "c^2 = \"sqrt%28625+%2B+7396%29\"
\n" ); document.write( "c = 89.6 ft
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