document.write( "Question 452573: The line of sight from a small boat to the light at the top of a 45-foot lighthouse built on a cliff 25 feet above the water makes a 39 degree angle with the water. To the nearest foot, how far is the boat from the cliff? \n" ); document.write( "
Algebra.Com's Answer #311148 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The line of sight from a small boat to the light at the top of a 45-foot \n" ); document.write( " lighthouse built on a cliff 25 feet above the water makes a 39 degree angle with the water. \n" ); document.write( "To the nearest foot, how far is the boat from the cliff? \n" ); document.write( ": \n" ); document.write( "Let d = distance to the base of the cliff (side adjacent to 39 degree angle) \n" ); document.write( "25 + 45 = 70'; height of lighthouse, side opposite 39 degree angle \n" ); document.write( ": \n" ); document.write( "Tan(39) = \n" ); document.write( "d = \n" ); document.write( "d = 86 ft from the base of the cliff \n" ); document.write( ": \n" ); document.write( "Distance from the boat to the cliff (c) itself which is 25' ft above the base, use pythag \n" ); document.write( "c^2 = 25^2 + 86^2 \n" ); document.write( "c^2 = \n" ); document.write( "c = 89.6 ft \n" ); document.write( " |