document.write( "Question 452610: There are 96 coins consisting of pennies,dimes, and quarters. the number of pennies is equal to the number of dimes and the total value is $22.05. How many coins of each tyoe are there? \n" ); document.write( "
Algebra.Com's Answer #311140 by ankor@dixie-net.com(22740)\"\" \"About 
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There are 96 coins consisting of pennies, dimes, and quarters.
\n" ); document.write( "p + d + q = 96
\n" ); document.write( ":
\n" ); document.write( "number of pennies is equal to the number of dimes
\n" ); document.write( "p = d
\n" ); document.write( ":
\n" ); document.write( "and the total value is $22.05.
\n" ); document.write( ".01p + .10d + .25 = 22.05
\n" ); document.write( "multiply by 100 to get rid of the decimals
\n" ); document.write( "p + 10d + 25q = 2205
\n" ); document.write( ":
\n" ); document.write( "Since d = p we can rewrite the 1st equation to:
\n" ); document.write( " 2p + q = 96
\n" ); document.write( "q = (96-2p)
\n" ); document.write( ":
\n" ); document.write( "and
\n" ); document.write( "also rewrite the value equation to
\n" ); document.write( "11p + 25q = 2205
\n" ); document.write( ":
\n" ); document.write( "Replace q with (96-2p)
\n" ); document.write( "11p + 25(96-2p) = 2205
\n" ); document.write( "11p + 2400 - 50p = 2205
\n" ); document.write( "11p - 50p = 2205 - 2400
\n" ); document.write( "-39p = -195
\n" ); document.write( "p = \"%28-195%29%2F%28-39%29\"
\n" ); document.write( "p = 5 pennies
\n" ); document.write( "then
\n" ); document.write( "d = 5 dimes
\n" ); document.write( "and
\n" ); document.write( "96 - 10 = 86 quarters
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check by finding the value
\n" ); document.write( ".01(5) + .10(5) + .25(86) =
\n" ); document.write( ".05 + .50 + 21.50 = 22.05; confirms our solutions of:
\n" ); document.write( "5 pennies, 5 dimes, 86 quarters\r
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