document.write( "Question 447480: the rate of a plane in calm air is 140 mph. flying with the wind, the plane can fly 450 miles in 2 hours less time than is required to make the return trip against the wind. find the rate of the wind. \n" ); document.write( "
Algebra.Com's Answer #311129 by jorel1380(3719)\"\" \"About 
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450/(140+x)+2=450/(140-x)
\n" ); document.write( "450(140-x)+2(140+x)(140-x)=450(140+x)
\n" ); document.write( "63000-450x+39200-2x2=63000+450x
\n" ); document.write( "39200-900x-2x2=0
\n" ); document.write( "0=2x2+900x-39200
\n" ); document.write( "0=x2+450x-19600
\n" ); document.write( "(x+490)(x-40)=0
\n" ); document.write( "x=-490 or 40
\n" ); document.write( "Throwing out the negative answer, we get the wind speed to be 40 mph..
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