document.write( "Question 447480: the rate of a plane in calm air is 140 mph. flying with the wind, the plane can fly 450 miles in 2 hours less time than is required to make the return trip against the wind. find the rate of the wind. \n" ); document.write( "
Algebra.Com's Answer #311129 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! 450/(140+x)+2=450/(140-x) \n" ); document.write( "450(140-x)+2(140+x)(140-x)=450(140+x) \n" ); document.write( "63000-450x+39200-2x2=63000+450x \n" ); document.write( "39200-900x-2x2=0 \n" ); document.write( "0=2x2+900x-39200 \n" ); document.write( "0=x2+450x-19600 \n" ); document.write( "(x+490)(x-40)=0 \n" ); document.write( "x=-490 or 40 \n" ); document.write( "Throwing out the negative answer, we get the wind speed to be 40 mph.. \n" ); document.write( " \n" ); document.write( " |