document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=452481>Question 452481</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Trains a and b sre traveling in the same direction on parallel tracks. Train a is traveling at 40 mile per hour and train b is traveling at 48 miles per hour. Train a passes a station at 7:25pm. If train b pass the same station at 7:40pm, what time will train b catch up to train a?\r<BR>\n" );
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document.write( "When will train B catch up with train A?<BR>\n" );
document.write( "__:____ am or pm\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #311085 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=311085\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Trains a and b sre traveling in the same direction on parallel tracks. Train a is traveling at 40 mile per hour and train b is traveling at 48 miles per hour. Train a passes a station at 7:25pm. If train b pass the same station at 7:40pm, what time will train b catch up to train a?<BR>\n" );
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document.write( "In 15 mins (740 - 725) train A goes 10 miles (40 mph * 1/4 hr)<BR>\n" );
document.write( "Train B gains on train A at 8 mph (48 - 40)<BR>\n" );
document.write( "10/8 = 1.25 hours<BR>\n" );
document.write( "740 + 115 = 855 PM\r<BR>\n" );
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