document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=46883>Question 46883</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I really need some help with this question.  Can anyone explain it to me?<BR>\n" );
document.write( "Thanks!\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The volume V of a square based pyramid with base sides s and height h is:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "V = 1/3 s^2 h\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "If the height is half of the length of a base side, express the volume V as a function of s. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31104 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31104\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We are given the formula for the volume<BR>\n" );
document.write( "V = 1/3 * s^2 * h<BR>\n" );
document.write( "Now this formula gives us the volume in terms of BOTH the side and the height.<BR>\n" );
document.write( "If we know the height is equal to half the side, we can write<BR>\n" );
document.write( "h = (1/2)s<BR>\n" );
document.write( "That allows us to substitute (1/2)s in for h in the original formula so that we have the volume in terms of ONLY the side...thus we get<BR>\n" );
document.write( "V = 1/3 * s^2 * h<BR>\n" );
document.write( "V = 1/3 * s^2 * (1/2)s<BR>\n" );
document.write( "V = (1/6)s^3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );